Hello,is it possible to use the Tempsensor AD22100 from Analog Devices with the k8055?Or do i need an Amplifier?After Connection i only got points in the Range from 92 til 102.
Hillybilly
Accordinbg to the datasheet the output voltage is:
VOUT = (V+/5 V) × (1.375 V +(22.5 mV/°C) × TA)
V+ = 5.0 V, TA = −50°C, output voltage is 0.250V, K8055 reading is 12
V+ = 5.0 V, TA = +150°C, output voltage is 4.750V, K8055 reading is 242
Your readings seem to be OK.
At 25°C the output voltage is 1.9375V
The reading from the K8055 is 255*1.9375V/5V = 98
To get more swing you have to use a differential amplifier. Connect the AD22100 to the other input and a fixed voltage to the other input of teh amplifier.
If you want to measure temperatures above 0°C, put 1.375V to the other input of the amplifier.
sorry,but i dont understand not all of it.Can you give me a small drawing of it?Excuse me ,i am not really an electrican. 
what is a differential amplifier??
Hillybilly
A differential amplifiers amplify the voltage difference between two input signals.
Here is a link for more info about the operational amplifier applications:
allaboutcircuits.com/vol_3/chpt_8/1.html
You can use the existing amplifier on the K8055 board as a differential amplifier.
You can use the other input of the amplifier by adding R8 and an external trimmer potentiometer according to this circuit diagram:
If R8 = 10k then the gain is about 2.
Adjust the trimmer potentiometer output voltage to 2*1.375V = 2.75V.
You get from the K8055 reading 00 at 0°C and 255 at the temperature of 111°C.
Selecting higher value for the R8 you get higher gain and lower temperature range to measure.
Thanks for the goood and quick answers!
Hillybilly
I edited my last post.
This line is now modified:
Adjust the trimmer potentiometer output voltage to 2*1.375V = 2.75V.
Now there is correct voltage value.