K8055 analog inputs read same value

Hello

I’ve been messing with this thing for a bit now and finally found something to connect to the analog inputs. But I noticed that no matter what I do or how SK2 and SK3 are configured the analog inputs are controlled by input 2. With the demo software, when I change the pot 2 it changes both of them and when I put in a signal both inputs seem to be getting a signal even though it’s connected to input 2. Which I’m assuming is correct because I thought it might have been my code at first.

Basically input 1 doesn’t do anything but input 2 controls both.

Any ideas of why this might be happeing?

Also sorry if this is in the wrong place I looked through the board and wasn’t sure where to put this.

Thanks

If you have a multimeter, you can check the analog input voltages on pins 2 and 3 of IC3.
If both of the voltages are equal and controlled only by RV2 (ATT2) trimmer potentiometer, then there is some problem in the analog input section of the board.

If the voltages are not equal and each of them is individually controlled by the trimmer potentiometer, then the IC3 is defective.

Keep the jumper caps on SK2 and SK3 placed when testing.

Thanks for the quick reply.

Pin 3 reads what it should but pin 2 maxes out at ~.96 V and scales with pot 2, at 50% its at .48V etc.

Also I didn’t say this before but if I connect to analog input 1 nothing happens. The software reads pin 2 at whatever pin 3 is set at, I’m assuming that’s how this thing works, until I make the connection with the multimeter then it drops to down. Pot 1 had no effect on anything I did.

I checked all my connections to make sure I didn’t mess up any of the soldering and everything looks ok.

It seems that there is no connection between pin 1 of IC1 and pin 2 of IC3.
Please check the voltage on pin 1 of IC1.
Does pot 1 have any effect on the voltage?

I’m almost certain this is the problem although I have not yet verified it. If it is, I know what the problem is and I can remedy it very easily. Thanks for the help; I’m still relatively new to all this.