K8019 protocol

Kits General
1

Hello, to be short.
Can anyone help me with this issue. Therefore, i know to recive packets of bytes when the card its on the reader, but i can not figure out how to get the card ID from that representation of bytes.
For example, i have this numbers 0007625328 116,23152 on my card and this numbers are ID of that card, right?
And my representation of bytes looks like this: <42><9><1><74><0><74><5A><70>. This numbers are hex value of the numbers of bytes.
P.S.
Manual “Proximity Card Reader with USB Interface Protocol” of the card reader says nothing about my problem.
Thanks.

2

0007625328 116,23152The decimal number 0007625328 is equal to 745A70 in hexadecimal
The decimal number 116 is equal to 74 in hexadecimal
The decimal number 23152 should be in there too, but your values don’t seem to add up

<42><09><01><FF>   <74>   <00><74><5A><70>
3

[quote=“VEL448”]0007625328 116,23152The decimal number 0007625328 is equal to 745A70 in hexadecimal
The decimal number 116 is equal to 74 in hexadecimal
The decimal number 23152 should be in there too, but your values don’t seem to add up

<42><09><01><FF>   <74>   <00><74><5A><70>

[color=#4000FF]Thank you very much for yor answer.[/color]

If you look more closely you will see that second byte is 9 and from the official manual for protocol says:

[b]<42> = always 42 hex
[color=#FF0000]<??> = size (in bytes) of the entire packet[/color]

<??> = command byte

= always ff hex

<??>...<??> = optional extra data[/b]

And I have 9 bytes, right?
“<42><09><01><74><00><74><5A><70>”

When I try to read (on the same reader) with oficial Velleman softwer i get correct ID card.
Actually I would like to say that the reader works well and also my application.
Please, can you help me.

4

I’ve looked at the source code for the conversion formula

Your raw tag:
00745A70h

The first part is the complete number (00745A70h), padded with zeroes, shown as decimal (10 digits):
0007625328

The second part are the first 2 bytes of the number (0074h), shown as decimal:
116

The third part are the last 2 bytes of the number (5A70h), shown as decimal:
23152

= 007625328 116,23152

5

Thank you very much for your time and answer.
It is RESOLVED.