Dear Sirs (and fellow tinkerers)!
First the question, then the explanation: where in the circuit of K2636 could I put a switch (and in which way) to completely “switch off” the current (to completely stop the motor) - first I thought about just minimizing the rotation (both VR under the limit), but the instructions clearly says I shouldn’t. So what to do? Where to modify the circuit and how?
The explanation:
I am just thinking about getting a K2636 kit, to regulate my dremel tool. Bigger powerdrills have a “progressive” power button, but my device has only an on/off switch and I have ruined so many boards I tried to drill that I became fed up. First I was thinking to make only a on/off switch in a form of a pedal (pedal would control a power relay) (well, I wil probably make this anyway, there are so many other useful appplications.) Then I remembered, how the things work with the bigger power-drills: more you push the button, quicker it gets. And I went hunting for a suitable control device. First I looked thorough eBay, but started to doubt the quality and reliability. And came to a local reseller of Velleman, which had exactly a kit for me. With the exception that I can’t quickly switch off the power with this kit. I thought to myself, I will regulate it with the (already mentioned) relay at the power exit (or input, that is also the question actually)(regulate in a way that I use foot pedal, where there is a foot controlled potentiometer, like in wahs and volume pedals and sewing machines), but then I looked at the circuit and said to myself, there must be a way I won’t have to use a power relay, just make a switch somewhere in the circuit to cut the power. And do that in a way that I would be dealing with low DC (so it can go directly to the pedal, with no relay circuitry. The trimmers are directly in the high voltage path, so this is not the way - oh, is the whole low voltage DC circuitry really “floating” on high voltage AC? Should I use a photocoupler so somewhere? But where? Maybe it wouldn’t be bad to “rework” this kit in a way that would provide a “power off” function. It could be my question is extremely stupid and simple, but I got to know a little about the amps and stuff, but fairly nothing about AC power, electromotors and their regulation. Thanks for the answer!
jernej