Hi.
I am in the process of attatching an on/off switch (with an embedded fuse), like this one kjell.com/se/sortiment/el-v … ing-p37378.
I am wondering how many amp’s I should use for the fuse.
The specs for the printer (vertex3dprinter.eu/#specs) only says 100-240 volt AC, max 150W.
If I calculate the amps as an resistive load only (with a power factor of 1.0), I will have about 0.6 amps.
I am using the formula => Current = Watts divided by ( Volts multiplied with the power factor).
The power factor is 1 for pure resistive load, and 0.3 for an inductive load, like a motor.
I = 150 / ( 240 * 1.0 ) = 0.63 A for a pure resistive load.
I = 150 / ( 240 * 0.3 ) = 2.00 A for an induction motor with no load
A fuse for 2A should be enough. Is this assumption correct?
//Claes