The manual for the K1823 kit mentions max DC input but it only discusses AC and the board only has AC printed on it. I’m more interested in reducing 12vDC rather than AC to something lower. Can I simply connect a 12vDC power supply to the K1823 where it has connections for AC printed on the board? FYI, I’m aiming to output as close to 4.8v as I can. Thanks.
Yes, you can feed it DC.
Sorry to open an old thread but this closely relates to my question. I am trying to design an external battery power supply to use when away from electrical outlets. I have a device that uses a 9VDC 1Amp power supply and I have found some 9.6VDC 3600mAh battery packs. I would like to use the K1823 to reduce the 9.6VDC down to 9VDC. Will this be a problem with the K1823? I am also interested in knowing what kind of losses I could expect on this setup. Thanks in advance.
This will not work.
Most likely, the equipment will not mind that you supply 9.6V instead of 9V. After all, it will only supply 9.6V for a short while. Once the batteries start to wear, the voltage will drop.
Should it need exactly 9V, which we doubt, simply put a 1N4007 diode in series with your batteries. Simple, cheap and effective.